n^2-14n-20=0

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Solution for n^2-14n-20=0 equation:


Simplifying
n2 + -14n + -20 = 0

Reorder the terms:
-20 + -14n + n2 = 0

Solving
-20 + -14n + n2 = 0

Solving for variable 'n'.

Begin completing the square.

Move the constant term to the right:

Add '20' to each side of the equation.
-20 + -14n + 20 + n2 = 0 + 20

Reorder the terms:
-20 + 20 + -14n + n2 = 0 + 20

Combine like terms: -20 + 20 = 0
0 + -14n + n2 = 0 + 20
-14n + n2 = 0 + 20

Combine like terms: 0 + 20 = 20
-14n + n2 = 20

The n term is -14n.  Take half its coefficient (-7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
-14n + 49 + n2 = 20 + 49

Reorder the terms:
49 + -14n + n2 = 20 + 49

Combine like terms: 20 + 49 = 69
49 + -14n + n2 = 69

Factor a perfect square on the left side:
(n + -7)(n + -7) = 69

Calculate the square root of the right side: 8.306623863

Break this problem into two subproblems by setting 
(n + -7) equal to 8.306623863 and -8.306623863.

Subproblem 1

n + -7 = 8.306623863 Simplifying n + -7 = 8.306623863 Reorder the terms: -7 + n = 8.306623863 Solving -7 + n = 8.306623863 Solving for variable 'n'. Move all terms containing n to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + n = 8.306623863 + 7 Combine like terms: -7 + 7 = 0 0 + n = 8.306623863 + 7 n = 8.306623863 + 7 Combine like terms: 8.306623863 + 7 = 15.306623863 n = 15.306623863 Simplifying n = 15.306623863

Subproblem 2

n + -7 = -8.306623863 Simplifying n + -7 = -8.306623863 Reorder the terms: -7 + n = -8.306623863 Solving -7 + n = -8.306623863 Solving for variable 'n'. Move all terms containing n to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + n = -8.306623863 + 7 Combine like terms: -7 + 7 = 0 0 + n = -8.306623863 + 7 n = -8.306623863 + 7 Combine like terms: -8.306623863 + 7 = -1.306623863 n = -1.306623863 Simplifying n = -1.306623863

Solution

The solution to the problem is based on the solutions from the subproblems. n = {15.306623863, -1.306623863}

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